## Basic Electrical Circuits

1. What is required for electrons to move in a useful way?

Question 1 of 10

2. Is a contactor a switch or a load?

Question 2 of 10

3. How can you create more electrons?

Question 3 of 10

4. What does this symbol represent?

Question 4 of 10

5. Is a motor an inductive or a resistive load?

Question 5 of 10

6. If you put two 10W light bulbs in series the wattage of the circuit will….

Question 6 of 10

7. This is the symbol for

Question 7 of 10

8. A basic mercury bulb thermostat is a

Question 8 of 10

9. Which statement is False?

Question 9 of 10

10. If you have a small 16 gauge extension cord and a larger 12 gauge extension cord the best way to connect them is…

Question 10 of 10

1. Greg G says:

#10 is a bit misleading. Yes it makes no difference but the question asked what’s the best way…I’d rather have the 12 gauge first in case I unplug the 16 gauge for a power tool that requires higher amps.

1. Bryan Orr says:

Fair enough

2. Daniel R says:

If you have two 10w bulbs un series wont they draw half the amount of wattage each bejng 5w, still making total power consumed by the circuit 10w?
I got 9/10 except for this one…

1. Bryan Orr says:

No, both TOGETHER will draw half so each would be 1.25W when in series.

1. Kevin Miles says:

Number 6 question is wrong in a series circuit the wattage would increase. Series circuits amperage stays the same voltage adds so if you have 2 10w bulbs connected to 120v supply then the bulbs would produce 0.1666 amps each a single bulb would be 0.0833 amps. the wattage would be 10w for a single bulb or 20w for two bulbs. a light bulb is a fixed resistance it will not reduce in resistance in a series circuit.

1. Bryan Orr says:

Hello Kevin. It isn’t wrong, it’s just deceiving because while bulb is marked with a wattage is is actually just a fixed resistor.

2. Bryan Orr says:

Ohms law shows us that as resistance increases amperage (and thus wattage) decrease

2. Jamie Kitchen says:

Yeah I got it wrong too. I should have taken the time to run the numbers in my head. Double the resistance halves the current. You then split the voltage drop across each load so you get half the voltage times half the current across each load. 1/2 X 1/2 = 1/4. 1/4 times 2 equals 1/2. Damn.

3. Alex Murphy says:

Bryan Orr, you’re my hero.

But seriously, I’ve listened to all your podcasts and I am a strong supporter. I am working on an electrical trainer for our new techs right now with basic circuits, and am also trying to put together a curriculum for a training program for the company. Glad to see like minds out there!

1. Bryan Orr says:

I’ve never been a hero before… it feels… weird 🙂

Thanks for the support man, feel free to use anything we have on the site.

4. Paul V Sullivan says:

it been a while

5. Bret says:

Yes…series vs parrellell rules…