Basic Electrical Theory

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1. According to Ohm’s Law, increasing resistance in a circuit
 
 
 
 
 

Question 1 of 10

2. A 5KW heatstrip rated at 230V would draw how many amps at 23V?
 
 
 
 
 
 

Question 2 of 10

3. Electrons contain a _________ Charge
 
 
 
 

Question 3 of 10

4. Atoms with _______ electrons in the outer layer (Valance) generally make better Insulators
 
 
 
 

Question 4 of 10

5. Volts X Amps = ________
 
 
 
 

Question 5 of 10

6. A common example of an inductive load is
 
 
 
 

Question 6 of 10

7. 1 Volt is
 
 
 
 
 

Question 7 of 10

8. A _________ is an example of a switch
 
 
 
 

Question 8 of 10

9. 1 HP = _______ BTUs per Hr
 
 
 
 
 
 

Question 9 of 10

10. When you install a dimmer on a incandescent light bulb and add resistance to the circuit the light will dim and the amperage of the circuit will decrease.
 
 
 

Question 10 of 10


 

6 comments

  1. Avatar Jonathan Hoeppner says:

    I though P=EI and E=IR. To #5.

    1. Bryan Orr Bryan Orr says:

      Watts(P) = Amps(I) X Volts (E)

  2. Avatar Martin M says:

    Question number 2: I = P / U gives 5000W / 23V = 217 A

    No?

  3. Avatar Jamie Kitchen says:

    746 watts per hp. Should have read the question more closely and realized it was asking for Btu’s.

  4. Avatar Taylor Kristiansen says:

    For Question #2 can you please explain how you got to that answer!? 1 Kw = 1000W, so using P= E x I, I just did 5000W (5Kw) / 23 = 217 .. I’m super confused!

    1. Avatar Michael Liddle says:

      Instead of doing P=V x A. We convert 5 kW to 5000 watts. Divide 5000W / 230V = nominally 22 amps (21.73). We can now use ohms law to find the actual resistance of the 5kW strip with this information.

      R= V/A: R= 230V/21.73A. R=10.58
      now if we do 23V/10.58 we get 2.17 amps.

      So the answer is really found in finding the resistance in the 5kW strip.

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