#10 is a bit misleading. Yes it makes no difference but the question asked what’s the best way…I’d rather have the 12 gauge first in case I unplug the 16 gauge for a power tool that requires higher amps.

If you have two 10w bulbs un series wont they draw half the amount of wattage each bejng 5w, still making total power consumed by the circuit 10w?
I got 9/10 except for this one…

Number 6 question is wrong in a series circuit the wattage would increase. Series circuits amperage stays the same voltage adds so if you have 2 10w bulbs connected to 120v supply then the bulbs would produce 0.1666 amps each a single bulb would be 0.0833 amps. the wattage would be 10w for a single bulb or 20w for two bulbs. a light bulb is a fixed resistance it will not reduce in resistance in a series circuit.

Yeah I got it wrong too. I should have taken the time to run the numbers in my head. Double the resistance halves the current. You then split the voltage drop across each load so you get half the voltage times half the current across each load. 1/2 X 1/2 = 1/4. 1/4 times 2 equals 1/2. Damn.

But seriously, I’ve listened to all your podcasts and I am a strong supporter. I am working on an electrical trainer for our new techs right now with basic circuits, and am also trying to put together a curriculum for a training program for the company. Glad to see like minds out there!

Question #6 isn’t very specific. It just states if you have 2 10W bulbs the wattage would? Well it would stay the same ie the answer is neither…. As nothing has changed. it doesn’t say if you had one bulb and then ADDED a 2nd bulb the wattage would then do what?

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#10 is a bit misleading. Yes it makes no difference but the question asked what’s the best way…I’d rather have the 12 gauge first in case I unplug the 16 gauge for a power tool that requires higher amps.

Fair enough

If you have two 10w bulbs un series wont they draw half the amount of wattage each bejng 5w, still making total power consumed by the circuit 10w?

I got 9/10 except for this one…

No, both TOGETHER will draw half so each would be 1.25W when in series.

Number 6 question is wrong in a series circuit the wattage would increase. Series circuits amperage stays the same voltage adds so if you have 2 10w bulbs connected to 120v supply then the bulbs would produce 0.1666 amps each a single bulb would be 0.0833 amps. the wattage would be 10w for a single bulb or 20w for two bulbs. a light bulb is a fixed resistance it will not reduce in resistance in a series circuit.

Hello Kevin. It isn’t wrong, it’s just deceiving because while bulb is marked with a wattage is is actually just a fixed resistor.

Ohms law shows us that as resistance increases amperage (and thus wattage) decrease

Yeah I got it wrong too. I should have taken the time to run the numbers in my head. Double the resistance halves the current. You then split the voltage drop across each load so you get half the voltage times half the current across each load. 1/2 X 1/2 = 1/4. 1/4 times 2 equals 1/2. Damn.

Bryan Orr, you’re my hero.

But seriously, I’ve listened to all your podcasts and I am a strong supporter. I am working on an electrical trainer for our new techs right now with basic circuits, and am also trying to put together a curriculum for a training program for the company. Glad to see like minds out there!

I’ve never been a hero before… it feels… weird 🙂

Thanks for the support man, feel free to use anything we have on the site.

it been a while

Yes…series vs parrellell rules…

Question #6 isn’t very specific. It just states if you have 2 10W bulbs the wattage would? Well it would stay the same ie the answer is neither…. As nothing has changed. it doesn’t say if you had one bulb and then ADDED a 2nd bulb the wattage would then do what?

Hello, how can I move out of the way the ” little man Icon ” to be able to read the other person comments. Thank you

NO EXCUSES. DID IT ON THE FLY BUT IT ENFORCES THE FACT THAT THE FUNDAMENTALS ARE SO IMPORTANT AND ALWAYS NEED TO BE REFRESHED WITH US AS WEATHERED TECHNICIANS. YOU SHOULD HAVE SEEN THE DEBATE I AND ANOTHER TECH (76 YEARS YOUNG)HAD WITH THESE MILLENNIUM TECHS ON REMOVAL OF NONCONDENSIBLES FROM A R13 CHILLER AS THEY STATED THAT THE BEST WAY IS BLOWING IT OFF THE TOP OF THE CONDENSER.THEY GOT A GOOD LESSON ON R718,717,METHYL CHLORIDE SYSTEMS.